12x^2=26

Solution for 12x^2=26 equation:

12x^2=26

We move all terms to the left:

12x^2-(26)=0

a = 12; b = 0; c = -26;
Δ = b2-4ac
Δ = 02-4·12·(-26)
Δ = 1248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1248}=\sqrt{16*78}=\sqrt{16}*\sqrt{78}=4\sqrt{78}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{78}}{2*12}=\frac{0-4\sqrt{78}}{24}
=-\frac{4\sqrt{78}}{24}
=-\frac{\sqrt{78}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{78}}{2*12}=\frac{0+4\sqrt{78}}{24}
=\frac{4\sqrt{78}}{24}
=\frac{\sqrt{78}}{6}
$